There's also the
UPDATED after comment by @hadley: To drop columns a,c you could do:
subset command, useful if you know which columns you want:df <- data.frame( a = 1:10, b = 2:11, c = 3:12 )
df <- subset(df, select = c(a,c)) #откуда, что оставляю
UPDATED after comment by @hadley: To drop columns a,c you could do:
df <- subset(df, select = -c(a,c) ) #откуда, что выкидываю
Воу, воу! Столнкнулась с проблемой объединения столбцов. Ну так вот-с.
Решается это весьма просто.x = data.frame(a = 1:5, b=rnorm(5))y = data.frame(a = 7:11, b = seq(0, -5, -1))> x a b 1 1 -0.4552751 2 2 0.8366082 3 3 0.6694684 4 4 1.1653944 5 5 0.1074383> y a b 1 7 0 2 8 -1 3 9 -2 4 10 -3 5 11 -4z =data.frame(x,y) #добавляет столбцы справа. НЕОБХОДИМ одинаковый размер по строчкам!!!!> z a b a.1 b.1 1 1 -0.4552751 7 0 2 2 0.8366082 8 -1 3 3 0.6694684 9 -2 4 4 1.1653944 10 -3 5 5 0.1074383 11 -4> z1 =data.frame(c(x$a, y$a), c(x$b, y$b)) #соединяем стобцы x$a и y$a,#x$b, y$b => "наращиваем" столбцы вниз. Теперь нам пофиг на количество строк, но #вот количество столбцов должно быть одинаковым!!!> z1 c.x.a..y.a. c.x.b..y.b. 1 1 -0.4552751 2 2 0.8366082 3 3 0.6694684 4 4 1.1653944 5 5 0.1074383 6 7 0.0000000 7 8 -1.0000000 8 9 -2.0000000 9 10 -3.0000000 10 11 -4.0000000Cоединить два строковых вектора? Неееееет! Никогда! Низачто! R так просто не дается!И, блеать, ПОЛУЧИЛОСЬ ЖЕ!!!!> summary1$testname [1] stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf [7] stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf [13] stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf [19] stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf [25] stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf [31] stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf [37] stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf [43] stem-n-leaf stem-n-leaf Levels: stem-n-leaf > summary3$testname [1] stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf stem-n-leaf [8] stem-n-leaf stem-n-leaf Levels: stem-n-leaf> c(summary1$testname, summary3$testname) [1] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 [42] 1 1 1 1 1 1 1 1 1 1 1 1Но! Я тут подумала, и решила, а почему бы мне их сначала в чары не преобразовать?c(as.character(summary3$testname), as.character(summary1$testname)) [1] "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" [6] "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" [11] "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" [16] "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" [21] "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" [26] "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" [31] "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" [36] "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" [41] "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" [46] "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" "stem-n-leaf" [51] "stem-n-leaf" "stem-n-leaf" "stem-n-leaf"

Комментариев нет:
Отправить комментарий